This television series is the 181st most popular in Serbian Wikipedia. Article "Јагодићи: Опроштајни валцер" in Serbian Wikipedia has 16.6 points for quality (as of August 1, 2024). The article contains 6 references and 9 sections.
Since the creation of article "Јагодићи: Опроштајни валцер", its content was written by 9 registered users of Serbian Wikipedia and edited by 9 registered Wikipedia users in all languages.
Јагодићи: Опроштајни валцер is on the 181st place in local ranking of television series on Serbian Wikipedia in all the time.
The article is cited 25 times in Serbian Wikipedia and cited 25 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | Serbian: #109 10.2014 |
Global: #419199 02.2020 |
On 18 September 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: pager, Salvatore Schillaci, Hezbollah, UEFA Champions League, 2024–25 UEFA Champions League, 2024 Lebanon communication device explosions, Lyle and Erik Menéndez, Sean Combs, deaths in 2024, Shōgun.
In Serbian Wikipedia the most popular articles on that day were: Никола Брун, Салваторе Скилачи, Село гори, а баба се чешља, Пејџер, Сергеј Трифуновић, Маргита Стефановић, Риалда Кадрић, УЕФА Лига шампиона 2024/25., Дунав, Бела лађа.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(16.64+3.61+5.26+36+21.29)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
